plz... solve this question on paper ............
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sin 3A=cos (90-3A)
cos (90-3A)=cos (A-26)
90-3A=A- 26
116=4A
A=116/4
=29
cos (90-3A)=cos (A-26)
90-3A=A- 26
116=4A
A=116/4
=29
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