Question

Plz solve this question..plz fast​

Answer 1

Lt x->1 (1-x) tan(πx/2)

Left Lt

= Lt h->0 (1-1+h) tan (π(1-h)/2)

= htan(π/2)

= 0

Right Lt

= Lt h->0 (1-1-h) tan ( π(1+h)/2)

= -htan(π/2)

= 0

Left Lt = Right Lt

Hence Limit exist

Hence

Lt x->1 (1-x)tan(πx/2) = 0

Answer 2

Step-by-step explanation:

here your answer :-------;;;;;;;

Lt x->1(1-x) ×Lt x->tan(πx/2)

=

taking limit......

= (1-1)× tan(π/2)

=0.

i hope this is right and helps u.