Math, asked by Lovelit, 2 days ago

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Answered by itzbabygirl123
2

Answer:

best off luck for your exam jhute insaan

effective length of the rod that create the EMF due to z component of the field l=5sin53=4m

E

z

=4∗2∗4=32

effective length of the rod that create the EMF due to y component of the field l=0 m

E

y

=3∗2∗0=0

net EMF=32 volt

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