plz solve this question. quickly plz..... I need it urgent.
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sagar10031:
this is very easy question
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OA = 5 cm ( Radius of Bigger Circle)
OB = 3 cm ( Radius of Smaller Circle )
PA = PB = 12 cm ( The tangents drawn from one external point are equal )
Perimeter of Quadrilateral PAOB
= OA + PA + OB + PB
= 5 + 12 + 3 + 12
= 32 cm
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OB = 3 cm ( Radius of Smaller Circle )
PA = PB = 12 cm ( The tangents drawn from one external point are equal )
Perimeter of Quadrilateral PAOB
= OA + PA + OB + PB
= 5 + 12 + 3 + 12
= 32 cm
Hope you like it please mark as brainliest and follow me if you like my answer.
Answered by
1
i hope it is usefull for You
thanks
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