Physics, asked by shivaniyadav1160, 7 months ago

plz solve this question.

Resistivity of a conducting wire is 2.3*10^2 ohm meter and it's area of cross section is 2.0*10^-3 meter square and length will be 100 cm^2 . what will be its resistance. ​

Answers

Answered by daiseroyce
0

Answer:

1150 m ohm

1150 m ohmExplanation:

1150 m ohmExplanation:given: resistivity (p)=2.3*10^2

1150 m ohmExplanation:given: resistivity (p)=2.3*10^2 area of cross section (A)=2*10^-3

1150 m ohmExplanation:given: resistivity (p)=2.3*10^2 area of cross section (A)=2*10^-3 length (l)= 100cm^2=100*10^-4m

1150 m ohmExplanation:given: resistivity (p)=2.3*10^2 area of cross section (A)=2*10^-3 length (l)= 100cm^2=100*10^-4mto find: Resistance (R)=?

1150 m ohmExplanation:given: resistivity (p)=2.3*10^2 area of cross section (A)=2*10^-3 length (l)= 100cm^2=100*10^-4mto find: Resistance (R)=?formula:p=RA/L

1150 m ohmExplanation:given: resistivity (p)=2.3*10^2 area of cross section (A)=2*10^-3 length (l)= 100cm^2=100*10^-4mto find: Resistance (R)=?formula:p=RA/L solution:R=pL/A

1150 m ohmExplanation:given: resistivity (p)=2.3*10^2 area of cross section (A)=2*10^-3 length (l)= 100cm^2=100*10^-4mto find: Resistance (R)=?formula:p=RA/L solution:R=pL/A R=2.3*10^2*100*10^-4/2*10^-3

1150 m ohmExplanation:given: resistivity (p)=2.3*10^2 area of cross section (A)=2*10^-3 length (l)= 100cm^2=100*10^-4mto find: Resistance (R)=?formula:p=RA/L solution:R=pL/A R=2.3*10^2*100*10^-4/2*10^-3 R=2.3*10^3/2

1150 m ohmExplanation:given: resistivity (p)=2.3*10^2 area of cross section (A)=2*10^-3 length (l)= 100cm^2=100*10^-4mto find: Resistance (R)=?formula:p=RA/L solution:R=pL/A R=2.3*10^2*100*10^-4/2*10^-3 R=2.3*10^3/2 R=1150 m ohm

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