Question

plz solve this question urgently...

Answer 1

hope this is Ur answer dear

Answer 2

$Given : \lim_{n \to 3} \frac{x^2 - 9}{x^2 - x - 6}$

$= \ \textgreater \ \frac{(x)^2 - (3)^2}{x^2 + 2x - 3x - 6}$

$= \ \textgreater \ \frac{(x + 3)(x - 3)}{x(x + 2) - 3(x + 2)}$

$= \ \textgreater \ \frac{(x + 3)(x - 3)}{(x - 3)(x + 2)}$

$= \ \textgreater \ \lim_{n \to 3} \frac{x + 3}{x + 2}$

$= \ \textgreater \ \frac{3 + 3}{3 + 2}$

$= \ \textgreater \ \frac{6}{5}$


Hope this helps!