plz solve this question with full explanation.
In the figure, O is the centre of a circle passing through points A, B, C and D and angle ADC=120 degree. Find the value of x
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angle adc + angle abc (sum of opposite angle of quadliator is 180)
120+ angle abc = 180
angle abc = 60
angle acb = 90 ( angle in a semi circle)
angle acb + angle abc + angle cab = 180 ( by angle sum property of triangle)
90 + 60 + x = 180
x= 180-150
x = 30
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