plz solve this question with proper explanation...
Answers
HELLO THERE!
The Oxidation states of the elements that are not fixed can be found out, taking that the total oxidation state of a compound is zero (0).
1. HOCl₂
You have mistaken; there is no such compound! The correct question would be HClO₂.
We know that oxidation state of Hydrogen is +1 and that of Oxygen is -2. Let the oxidation state of Chlorine be x.
1 + 2(-2) + x = 0
=> x = +3
So, oxidation number of chlorine in this case is +3.
2. H₂O₂
Here we know that the Oxidation state of Hydrogen is 1. Let the oxidation state of oxygen be x.
(2 x 1) + 2x = 0
=> x = -1
So, oxidation state of oxygen in hydrogen peroxide is -1.
3. HNC
Oxidation state of Hydrogen = 1 and Carbon = 4 (though not always). Let the oxidation state of nitrogen be x.
Then,
Case 1: If C= + 4 and N = x,
1 + 4 + x =0
This gives oxidation state of nitrogen to be -5.
Case 2: If N = -3 and C = x,
1 - 3 + x = 0
This gives oxidation state of Carbon to be +2.
For the second question (finding Peroxide linkage, you need to know the maximum oxidation state of the element).
1. CrO₆
Maximum oxidation state of Chromium is +6.
However, we get to know that here, oxidation state of Chromium is:
x - 12 =0
=> x = + 12, which is not possible.
Number of peroxide linkage = (Calculated O.S. - Maximum O.S.)/2
= (12-6)/2
= 3
2. H₂SO₅ (known as Caro's acid):
Maximum Oxidation state of Sulphur = +6.
However, in Caro's acid, we find it to be:
2 + x - 10= 0
=> x = 8
Using the above formula,
Number of peroxide linkages:
(8-6)/2
= 1
HOPE MY ANSWER IS SATISFACTORY...
Thanks!