plz solve this questions dono questions me se ek ek solve kar do
Attachments:

Answers
Answered by
4
( 3 ) : ( ii )
{ ( x³ + 1 ) / ( x⁴ + 1 ) } × { ( x³ - 1 ) / ( x⁴ - 1 ) }
[ { x³ + 1 }{ x³ - 1 } ] / [ { x⁴ + 1 }{ x⁴ - 1 } ]


[ {x³+1}/{x⁴+1]×[{x³-1}{x⁴-1}]
[(x+1)(x²-x+1)/(x⁴+1)]×[(x-1)(x²+x+1)/(x²-1)(x²+1)]
[(x+1)(x²-x+1)/(x⁴+1)]×[(x-1)(x²+x+1)/(x-1)(x+1)(x²+1)]
[x²-x+1/x⁴+1 ] × [x²+x+1/x²+1]
[(x+1)²-x²]×[x^{6}+x⁴+x²+1]
4 : ( ii )
[(6x²+3x-2x-1)/(2x²-10x+3x-15)]×[(4x²-9)/(4x²+4x+1)]
[ {3x(2x+1)-(2x+1)}/{2x(x-5)+3(x-5)}]×[{(2x)²-(3)³}/{(2x+1)²]
[{(2x+1)(3x-1)}/{(x-5)(2x+3)}]×[{(2x+3)(2x-3)}/{(2x+1)}]
[(3x-1)/(x-5)]×[(2x-3)/(2x+1)]

{ ( x³ + 1 ) / ( x⁴ + 1 ) } × { ( x³ - 1 ) / ( x⁴ - 1 ) }
[ { x³ + 1 }{ x³ - 1 } ] / [ { x⁴ + 1 }{ x⁴ - 1 } ]
[ {x³+1}/{x⁴+1]×[{x³-1}{x⁴-1}]
[(x+1)(x²-x+1)/(x⁴+1)]×[(x-1)(x²+x+1)/(x²-1)(x²+1)]
[(x+1)(x²-x+1)/(x⁴+1)]×[(x-1)(x²+x+1)/(x-1)(x+1)(x²+1)]
[x²-x+1/x⁴+1 ] × [x²+x+1/x²+1]
[(x+1)²-x²]×[x^{6}+x⁴+x²+1]
4 : ( ii )
[(6x²+3x-2x-1)/(2x²-10x+3x-15)]×[(4x²-9)/(4x²+4x+1)]
[ {3x(2x+1)-(2x+1)}/{2x(x-5)+3(x-5)}]×[{(2x)²-(3)³}/{(2x+1)²]
[{(2x+1)(3x-1)}/{(x-5)(2x+3)}]×[{(2x+3)(2x-3)}/{(2x+1)}]
[(3x-1)/(x-5)]×[(2x-3)/(2x+1)]
DIVAYANSMAX:
thanx bro you are geanus
Similar questions