plz solve this questions with solution if the answer will correct and helpful i will add it to the brainlist answer.
don't spam
and don't send stupid answers AND I WILL ALSO FOLLOW THAT BRINLY user.......
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6) The starting time is 8:45a.m. and after reaching school, the time is 9:20 a.m.
The time taken = 9:20-8:45
=35 minutes
=35×60
=2100 seconds
Distance covered=1.25 km
=125/100
=5/4×1000
=1250mtrs.
The AVG. speed =1250/2100
=25/42 m/s
=(25/42)×(18/5)
=90/42
=2.142 km/hr
7) Length of tunnel is 600mtrs.
Length of train is 250mtrs.
Time taken is 1 minute i.e. 60 seconds
Speed1=600/60
=10m/s
Speed2=250/60
=4.1666
=4.17m/s
Speed of the train=Speed1+Speed2
=10+4.17
=14.17m/s
I hope that the answers are correct.
The time taken = 9:20-8:45
=35 minutes
=35×60
=2100 seconds
Distance covered=1.25 km
=125/100
=5/4×1000
=1250mtrs.
The AVG. speed =1250/2100
=25/42 m/s
=(25/42)×(18/5)
=90/42
=2.142 km/hr
7) Length of tunnel is 600mtrs.
Length of train is 250mtrs.
Time taken is 1 minute i.e. 60 seconds
Speed1=600/60
=10m/s
Speed2=250/60
=4.1666
=4.17m/s
Speed of the train=Speed1+Speed2
=10+4.17
=14.17m/s
I hope that the answers are correct.
AsutoshDikhit:
are the answers correct?
6 is correct
because I'm not sure if the first answer is correct
7 is wrong
ok I'm doing it again so if I'll be able to do it correctly
the 7 th answer have to be 14.17 m/s
okay
alright
Hey! I got the answer.
Check it out.
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