Question

plz solve this quick​

Answer 1

Answer:

${x}^{2} + \frac{1}{ {x}^{2} } \\ \frac{ {x}^{2} }{1} + \frac{1}{ {x}^{2} } \\ \frac{ {x}^{2} + 1 }{1 {x}^{2} } \\ \frac{ {2x}^{2} }{ {1x}^{2} } = {3 {x}^{4} }^{} = 3 \times 3 \times 3 \times 3 \\ 81 {x}^{4} \\ \\ \\ {x}^{4} + \frac{1}{ {x}^{4} } \\ \frac{ {x}^{4} }{1} + \frac{1}{ {x}^{4} } \\ \\ \frac{ {x}^{4} + 1 }{1 {x}^{4} } \\ \frac{1 {x}^{4} }{ {1x}^{4} }$