Question

Plz solve this...
Quick...
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Answer 1

Hiii,,,

So here is ur answer.....

d = mass/V

⇒ 10.5 g/cc means in 1 cc

⇒ 10.5 g of Ag is present.

Number of atoms of Ag in 1 cc

⇒ 10.5/108 × Na

In 1 cm, number of atoms of Ag = (10.5/108 × Na)^1/3

In 1 cm², number of atoms of Ag = (10.5/108 × Na)^2/3

In 10^ -12 m² or 10^ -8 cm², number of atoms of Ag = (10.5/108 × Na)^2/3 × 10^ -8

⇒ ((1.05 × 6.022 × 10^24)/108)^2/3 × 10^ -8

⇒ 1.5 × 10^7

So, x = 7

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