Question

plz solve this quick i will follow you also i promise❤️​

Answer 1

Question :

Divide using factorisation

  (81x² - 81) ÷ (x - 1)

Answer :

= 81(x + 1)

Step-by-step explanation :

 

$=\frac{81x^2-81}{(x-1)} \\\\ =\frac{81(x^2-1)}{x-1} \\\\ = \frac{81(x^2-1^2)}{x-1} \\\\\\ By \ using \ the \ identity, \\\\ \boxed{\bf a^2-b^2=(a+b)(a-b)} \\\\\\ =\frac{81(x+1)(x-1)}{x-1} \\\\ =81(x+1)$

Answer 2

Answer:

Answer :

= 81(x + 1)

Step-by-step explanation :

 

\begin{gathered}=\frac{81x^2-81}{(x-1)} \\\\ =\frac{81(x^2-1)}{x-1} \\\\ = \frac{81(x^2-1^2)}{x-1} \\\\\\ By \ using \ the \ identity, \\\\ \boxed{\bf a^2-b^2=(a+b)(a-b)} \\\\\\ =\frac{81(x+1)(x-1)}{x-1} \\\\ =81(x+1)\end{gathered}=(x−1)81x2−81=x−181(x2−1)=x−181(x2−12)By using the identity,a2−b2=(a+b)(a−b)=x−181(x+1)(x−1)=81(x+1)