Question

plz solve this quickly​

Answer 1

Step-by-step explanation:

secθ-tanθ=k

w/k,

sec²θ-tan²θ=1

(secθ-tanθ)(secθ+tanθ)=1

k(secθ+tanθ)=1

secθ+tanθ=1/k

Answer 2

$\huge\sec\theta - tan \theta = k - - - (1) \\ \\ \bf\pink{we \: know \: that} \\ \\ \bf{ \underline{ \overline{ \mid{ {sec}^{2 }\theta - {tan}^{2} \theta = 1 }} \mid} } \\ \\ \bf\ \implies: (sec \theta - tan \theta)(sec \theta + tan\theta) = 1 \\ \\ \bf\ \implies: k(sec \theta + tan\theta) = 1\\ \\ \red{\boxed{ \underline{ \overline{ \mid{{ \implies: (sec \theta + tan\theta) = \frac{1}{k} }}}} \mid}}$