Math, asked by sidhuizm07Raman, 1 year ago

plz solve this qus??!!!

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Answered by sivaprasath
0
=(1/a + 1/b)÷(1/ab)+(1/a -1/b)÷(1/a²-1/b²)            ⇒a^-1=1/a
=(1/a+1/b)×(ab)+(1/a-1/b)×(a²-b²)                         ⇒1/a÷1/b=1×b/a
=(b+a)+(1/a-1/b)(a+b)(a-b)                                     ⇒a²-b²=(a+b)(a-b)
=a+b+(a+b-((a³-b³)/ab)                                           ⇒(1/a-1/b)(a+b)(a-b)=(a³-b³/ab)
                            
                            !!Hope it helps!!,if possible and accurate, mark as BRAINLIEST.
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