Question

plz solve this Solve (4pq+3q)²- (4pq-3q)².​

Answer 1

Answer:

4pq + 3q)² – (4pq – 3q)² = 48pq²

As we know,

(a + b)² = a² + b² + 2ab

and

(a – b)² = a² + b² – 2ab

So, we have to apply the above identities in the given equation.

(4pq + 3q)² – (4pq – 3q)² = L.H.S.

= (16p²q² + 9q² + 24pq²) – (16p²q² + 9q² – 24pq²)

= 16p²q² + 9q² + 24pq² – 16p²q² – 9q² + 24pq²

= 24pq² + 24pq²

= 48pq²

= R.H.S.

Answer 2

${(4pq + 3q)}^{2} - {({4pq + 3q)}}^{2} \\ (16 {p}^{2} {q}^{2} + 9 {q}^{2} ) - (16 {p}^{2} {q}^{2} + 9 {q}^{2} ) \\ 16 {p}^{2} {q}^{2} + 9 {q}^{2} - 16 {p}^{2} {q}^{2} - 9 {q}^{2} \\ 0$