plz solve this
solve 5th one
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maybe be correct this one
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tanishak88:
what you name
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Anil runs = 60 m
no. of times =4
distance he covered= 60×4
= 240 m
Vinay runs twice a rectangular field= length 180m and breadth 110 m ok
= (2× l+b)
= 2× 180+110
= 2×290
= 480m
Vinay runs twice so again we will multiply by 2
So, 480×2
=960 m
anil covers 240 ( < ) Vinay covers 960
so, Vinay covers more than anil
now we have to check by how much Vinay covers from anil
So, 240m - 960m
= 720m
no. of times =4
distance he covered= 60×4
= 240 m
Vinay runs twice a rectangular field= length 180m and breadth 110 m ok
= (2× l+b)
= 2× 180+110
= 2×290
= 480m
Vinay runs twice so again we will multiply by 2
So, 480×2
=960 m
anil covers 240 ( < ) Vinay covers 960
so, Vinay covers more than anil
now we have to check by how much Vinay covers from anil
So, 240m - 960m
= 720m
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