Question

Plz solve this statistics problem

Answer 1

$cf \\ 5 \\\ 5 + x \\ 25 + x \\ 40 + x \\ 45 + x + y \: \\ \frac{n}{2} = \frac{60}{2} = 30 \\ cf = 5 + x \\ f = 20 \\ h = 10 \\ 45 + x + y = 60 \\ x + y = 15....(1) \\ median = l + \\ ( \frac{n}2 - cf ) \times h \: \: divided \: byf \\ given \: median = 28.5 \\ 28 .5 = 20 + \frac{30 - (5 + x)} {20} \times 10 \\ 28.5 - 20 = \frac{30 - 5 - x}{20} \times 10 \\ 8.5 = \frac{25 - x}{20} \times 10 \\ 8.5 \times 2 = 25 - x \\ x = 8 \\ put \: x \: in \: eqn \: (1) \\ 45 + x + y = 60 \\ 45 + 8 + y = 60 \\ y = 7 \\ \\ \\ so \: x = 8 \: \: y = 7$