Question

plz solve this step by step then only I will mark ur answer brainliest ok plz​

Answer 1

Answer:

3) Sum of all angles around a point = 360°

So,

∠AOB + ∠BOC + ∠COD + ∠DOE + ∠EOA = 360°

112° + 90° + 86° + x + 3x = 360°

or 4x + 288 = 360°

or 4x = 360° - 288°

or 4x = 132

or x = 132/ 4

or x = 33

∠DOE = x = 33°

∠EOA = 3x = 33° × 3 = 99°

2) Sum of all angles around a point = 360°

∠AOB + ∠BOC + ∠COD + ∠DOA = 360°

or x + 2x + 3x + 4x = 360°

or 10x = 360°

or x = 360/10

or x = 36

∠AOB = x = 36°

∠BOC = 2x = 2 × 36° = 72°

∠COD = 3x = 3 × 36° = 108°

∠DOA = 4x = 4 × 36° = 144°

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