plz solve this stepwise
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consider ABCD is a square with sides
AB = BC = CB = DA= a
and DB = AC are the diagonals
in triangle ABD
AD² + AB² = DB²
=> a² + a² = DB²
=> 2a² = DB²
=> a = DB/√2
=> a = 1/√2 x DB
HERE
a is the side and DB is the diagonal
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