plz solve this sum
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Answered by
1
Answer:
let the three muliples be 11x,11x+11,11x+22
11x+11x+11+11x+22=363
33x+33=363
33x=330
x=10
Answered by
1
Answer:
let first multiple= x,
second multiple= x+11,
third multiple=x+22
atq
x+x+11+x+22=363
3x+33=363
3x=363-33
x=330/3
x=110
so answer=110, 121, 131
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