Question

plz solve this sum.....

Answer 1

just remember one rule
${i}^{4n} = 1$
when power is a mutiple of 4 i results 1
592 596 600 will give 1
now
${i}^{4n + p} = {i}^{p}$
where p=1,2,3 only
594 will results in i square
598 will result in i square and so will 602
now i square is -1
so putting the values
ans is 1