Question

plz solve this sum ch 4 ex 4.3 class 10​

Answer 1

Answer:

1. b^2-4ac=(4√3)^2-4×4×3=0=48-48=0=(2x)^2+2×2x.√3+(√3)^2-(√3)^2+3=0=(2x+3)^2=0=2x=-√3=x=-√3/2,-√3/2