Question

plz solve this sum.. it's of class 10th... thank you for helping...

Answer 1

hcf of 65 117 is 13
so a/q
13=65m-117
13+117/65=m
m=130/65
m=2

hope this helps u :)

Answer 2

Prime factorization of 65 = 5 * 13

Prime factorization of 117 = 3 * 3 * 13

HCF(65,117) = 13.

Given that HCF(65,117) = 65m - 117.

65m - 117 = 13

65m = 13 + 117

65m = 130

m = 130/65

m = 2.


Therefore the value of m = 2.


Note: This question can also be solved using Euclid's division algorithm.


Hope this helps!