Question

plz solve this today is my maths test
any one can solve this I will give 100 rs
in paytm​

Answer 1

Answer:

this is the answer for your Question

Answer 2

Answer:

Q1) 23/99

Step-by-step explanation:

Q1)    0.2323232323....

        Here, x = 0.2323 .......(i)......

(Let x be the required fraction)

∵ Bar is over 2 places after decimal,

∴ 10² x = 0.2323 * 10²

⇒ 100x = 23.2323  .....(ii).......

Take care that you have to keep same number of decimal places in first and second equations.

Now, subtract eqn.(i) from eqn.(ii),

⇒ 100x - x = 23.2323 - 0.2323

⇒ 99x = 23

⇒ x = 23 / 99

Q2) LHS = [x^a(b-c) / x^b(a-c)][x^b / x^a]^c

Let's solve,

⇒ [x^(ab-ac) / x^(ba-bc)] / [x^(b-a)]^c

   (∵ x^m / x^n = x^(m-n))

⇒ [x^(ab-ac-(ba-bc))] / [x^(b-a)]^c

   (∵ x^m / x^n = x^(m-n)) Also, take care of signs.

⇒ [x^(ab-ac-ba+bc)] / [x^(b-a)]^c       (∵ ab = ba, so let's remove it)

⇒ [x^(bc-ac)] / [x^(b-a)]^c

⇒ [x^(bc-ac)] / [x^(bc-ac)]

    (∵ [x^(a+b)]^m = x^(am + bm))

⇒ [x^((bc-ac)-(bc-ac))]

      (∵ x^m / x^n = x^(m-n)) Also, take care of signs.

⇒ [x^(bc-ac-bc+ac)]

⇒ [x^0]     (Because bc - bc = 0 and -ac + ac = 0 and 0+0 = 0)

⇒ 1            (m^0 = 1)

=  RHS

Hence proved.