plz solve this .....
tomorrow is my board exam.........
Answers
can u remember me we have talked day before today .
Answer:
266/7
Step-by-step explanation:
Hey mate!!
One thing that i wanna tell you tomorrow is also my Board Exam Of Math's
Your answer is here:-
Let A be the are of the shaded region. Then,
A=2(area of Quadrant ABPD - area of triangle ABD)
First to make it easy,we will calculate both of the areas separately:
So,here we go:
Area of Quadrant ABPD = π÷4×(8)²
=22/7×1/4×64
=22/7×16
=352/7
Now, we will calculate,
area of triangle ABD,
So, here we go:
Are of triangle ABD = 1/2×base×height
=1/2×8×8
=8×4
=32
Now we will calculate the area of the shaded region:
A=2(area of Quadrant ABPD - area of triangle ABD)
A=2(352/7-32)
A=2(352-224/7)
A=256/7
Hence your answer is 266/7 mate!!
Please mark me as brainliest
