Question

plz solve this .....

tomorrow is my board exam.........

Answer 1

can u remember me we have talked day before today .

Answer 2

Answer:

266/7

Step-by-step explanation:

Hey mate!!

One thing that i wanna tell you tomorrow is also my Board Exam Of Math's

Your answer is here:-

Let A be the are of the shaded region. Then,

A=2(area of Quadrant ABPD - area of triangle ABD)

First to make it easy,we will calculate both of the areas separately:

So,here we go:

Area of Quadrant ABPD = π÷4×(8)²

                                        =22/7×1/4×64

                                        =22/7×16

                                        =352/7

Now, we will calculate,

area of triangle ABD,

So, here we go:

Are of triangle ABD = 1/2×base×height

                                =1/2×8×8

                                =8×4

                                =32

Now we will calculate the area of the shaded region:

A=2(area of Quadrant ABPD - area of triangle ABD)

A=2(352/7-32)

A=2(352-224/7)

A=256/7

Hence your answer is 266/7 mate!!

Please mark me as brainliest