Question

plz...solve this urgent
I will mark you as brainiest but step by step solution needed​

Answer 1

$\frac{1}{ log_{3}(2) } + \frac{2}{ log_{9}(4) } + \frac{3}{ log_{27}(8) } \\ log_{2}(3) + \frac{2}{ log_{9}( {2}^{2} ) } + \frac{3}{ log_{27}( {2}^{3} ) } \\ log_{2}(3) + \frac{2}{2 log_{9}(2) } + \frac{3}{3 log_{27}(2) } \\ log_{2}(3) + \frac{1}{ log_{9}(2) } + \frac{1}{ log_{27}(2) } \\ log_{2}(3) + log_{2}(9) + log_{2}(27) \\ log_{2}(3) + 2 log_{2}(3) + 3 log_{2}(3) \\ 6 log_{2}(3)$