Question

plz solve this urgent tomorrow exam

Answer 1

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$x {}^{3} - 23x {}^{2} + 142x - 120$
x^3 - x^2 -22x^2 +22x +120x-120

=x^2(x-1) -22x(x-1) + 120(x-1)

=(x-1)(x^2-22+120)

=(x-1)(x^2- 12x-10x+120)

=(x-1){ x(x-12)-10(x-12)}

=(x-1)(x-12)(x-10)
$(x - 1)(x - 10)(x - 12)$

Mark it