plz solve this. Urgently required
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HeY USER HERE IS YOUR ANSWER :-
7x - 5y = 17 ----------------(1)
3x + 7y = -11 --------------(2)
multiply (1) by 3 and (2) by 7
we get , 21x - 15y - 51 = 0 -------(3)
21x + 49y +77 = 0 --------(4)
Subtract (3) from (4)
21x - 15y - 51 = 0
21x + 49y + 77 = 0
(-) (-) (-)
------------------------------
- 64 - 128y = 0
-------------------------------
128y = -64
y = -64 / 128
y = -2
put this value of y in (1) or (2) to get x
we get , 7x - 5(-2) = 17
7x + 10 = 17
7x = 17-10
x = 7/7
x = 1
HOPE IT HELPS YOU !!!!!
Answered by
0
Given eqns : 7x - 5y = 17 ......(1)
3x + 7y = - 11 ......(2)
Multiply by 3 in eq. 1 and by 7 in eq. 2
21x - 15y = 51 ......(3)
21x + 49y = -77 ....(4)
sub eq. 3 and 4
- 64y = 128
y = -2
put y = -2 in eq 2
3x + 7 × -2 = -11
x = 1
hence , x= 1 and y = -2
hope you will understand it...
3x + 7y = - 11 ......(2)
Multiply by 3 in eq. 1 and by 7 in eq. 2
21x - 15y = 51 ......(3)
21x + 49y = -77 ....(4)
sub eq. 3 and 4
- 64y = 128
y = -2
put y = -2 in eq 2
3x + 7 × -2 = -11
x = 1
hence , x= 1 and y = -2
hope you will understand it...
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