Question

plz solve this using quadriatic formula

Answer 1

Question is x²-(√2 + 1)x + √2 =0

now using Quatratic Formulae.

D=√(b²-4ac)
D=√[(√2+1)² -4√2]
=2-2√2+1-4√2
=3-6√2

Now x=[-b±√D]/2a

So we get::

→x=[√2+1±√(3-6√2)]/2

Answer 2

$Answer : \boxed{\sqrt{2},1}}$

Hope it helps