plz solve this very important
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First of all let discuss about this problem little more.
As we know when a force is acting about a fix point it creates moment about that point.
In Given problem the forces are the weight of boys.
Now moment created by the weight 40kgf
= weight x perpendicular distance from fixed point
=WxD
=40x(2.5-1.5)
=40x1
M1=40kgf-m
(D=total distance of end of the see-saw - distance of weight from free end or end of sew-saw)
Now for balancing the moment right side to the center must equal to moment left side to the center
M1=M2
40=25 x D
D=40/25
D=1.6
1.6m is the distance from center.
Distance from end =2.5-1.6=0.9m
This is your ans hope it will help you in case of any doubt comment below
As we know when a force is acting about a fix point it creates moment about that point.
In Given problem the forces are the weight of boys.
Now moment created by the weight 40kgf
= weight x perpendicular distance from fixed point
=WxD
=40x(2.5-1.5)
=40x1
M1=40kgf-m
(D=total distance of end of the see-saw - distance of weight from free end or end of sew-saw)
Now for balancing the moment right side to the center must equal to moment left side to the center
M1=M2
40=25 x D
D=40/25
D=1.6
1.6m is the distance from center.
Distance from end =2.5-1.6=0.9m
This is your ans hope it will help you in case of any doubt comment below
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