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----------------HEY DEAR--------------------
HERE IS YOUR ANSWER................
WE KNOW ,
WHENEVER A DIAMETER MAKE ANGLE IN THE SEMI CIRCLE THEN IT S 90 DEGREE
SO IN THIS AD IS DIAMETER AS O IS CENTRE
SO ,
angle ACD = 90 DEGREE
ANGLE ACB = ANGLE BCD - 90 DEGREE
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HOPE IT HELPS YOU..
THANKS..
lalitmohansingpc67zt:
thank you so much.
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If angle bcd =90 than angle bac= 90 ( oc is a diameter )
I hope these W ill helps u
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