plz solve thus question 14
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here is your answer
I hope it will help u
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(3/5)^3 × (3/5)^-6 = (3/5)^2x-1
Calculate the product
➾ (3/5)^-3 = (3/5)^2x-1
Set the exponents equal
➾ -3 = 2x - 1
Move the terms
➾ -2x = -1 + 3
Calculate
➾ -2x = 2
Divide both the sides by -2
∴
Calculate the product
➾ (3/5)^-3 = (3/5)^2x-1
Set the exponents equal
➾ -3 = 2x - 1
Move the terms
➾ -2x = -1 + 3
Calculate
➾ -2x = 2
Divide both the sides by -2
∴
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