Question

plz solve two sum's!!!!!​

Answer 1

Answer:

only add karna h dono ma

Answer 2

Answer:

1. considering ptrs as trapezium

finding area of trapezium ptrs

trapezium area's formula

trapezium area = ( sum of lenght of parallel side into ) × height

parallel side = pr=10 ans ts=6 , height is tu =4

trapezium area =( 10 + 6 ) × 4

area = 16 × 4

area of trapezium= 64 sqcm

now finding area of triangle pqr

base = pr = 10 , height =5

area of triangle = 1/2 × base × height

area = 1/2×10×5( dividing 10 by 5 )

area = 5×5

area of triangle = 25 sqcm

area of pqrst = ptrs + pqr

area of polygon pqrst = 64 + 25 = 89 sqcm

considering def as right angel triangle