plz solve. u=7,a=?,t=4s=ut+1/2at square.
Shrirao:
can u tell me what can i write
ya
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◆ u = 7 m/s
◆ a = ?
◆ t = 4 s
◆ S (distance) = speed (u) × time (t) = (7×4) m
= 28 m.
Using 2nd equation of motion, we get :
S = ut + 1/2 at^2
=> 28 = 7×4 + 1/2 × a × (4)^2
=> 28 =28 + 1/2 × 16 a
=> 28 - 28 = 1/2 × 16 a
=> 0 = 1/2 × 16a
=> 1/2 × 16 a = 0
=> 16/2 a = 0
=> 8 a = 0
=> a = 0/8 = 0 m/s^2 [Answer]
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◆ a = ?
◆ t = 4 s
◆ S (distance) = speed (u) × time (t) = (7×4) m
= 28 m.
Using 2nd equation of motion, we get :
S = ut + 1/2 at^2
=> 28 = 7×4 + 1/2 × a × (4)^2
=> 28 =28 + 1/2 × 16 a
=> 28 - 28 = 1/2 × 16 a
=> 0 = 1/2 × 16a
=> 1/2 × 16 a = 0
=> 16/2 a = 0
=> 8 a = 0
=> a = 0/8 = 0 m/s^2 [Answer]
● IF YOU LIKE MY ANSWER, PLEASE MARK ME AS BRAINLIEST MATE...............!!!!!!!!
FOLLOW ME FOR MORE SOLUTIONS OF YOUR DOUBTS..........!!!!!!!!
BE BRAINLY........!!!!!!!! ●
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