Question

plz solve urgently by differentiation class 11​

Answer 1

[tex]Heya \: \: \\ \\ y(x) =1 \div \sqrt{2x} \\ \\ y (x) = (2x) {}^{ - 1 \div 2} \\ \\ y (x) = 2 {}^{ - 1 \div 2} \times (x) {}^{ - 1 \div 2} \\ \\ y {}^{1} (x) = (2) {}^{( - 1 \div 2)} \times ( - 1 \div 2) \times x {}^{ - (3 \div 2)} \\ \\ y {}^{1} (x) = - 2 {}^{( - 3 \div 2)} \times x {}^{( - 3 \div 2)} \\ put \: x = 2 \\ \\ y {}^{1} (2) = - 2 {}^{( - 3 \div 2)} \times -2{(-3/div 2)} \\ \\ y {}^{1} (2) = - (1 \div 8)

Answer 2

$if \\ x = 2 \\ then \\ \\ y = 1 \div \sqrt {2 \times 2 } \\ \\ y = 0.5$

hey mate this is your Ans ....