plz solve with explain plz fast
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Anonymous:
is it option A
BCOZ we will apply the parallel axis theorem here
than solve
with explain
that is I° + m (length from the centre)^2
hlw here ni
answer do
Maine Q send kiya hai vaha
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Hola User______________
Here is Your Answer...!!!
_______________________
⭐Actually welcome to the concept of the ROTATIONAL Dynamics...
⭐Basically we know that ... to find the Moment of inertia along any axis parallel to the Central Axis of the rotation is given as ...
⭐Ip = Icm + M ( length or dimension from the centre of the body to the point on which to find inertia )^2 .
⭐So applying here as given ....we get
⭐Moment of inertia of the axis passing through the midpoint perpendicular to the length is = l°
⭐And to find the inertia from the midpoint to the end of rod ...
⭐The effective lenght will L/2 as we are counting from the mid point ...
⭐Thus substituting in above formula we get ...
⭐Ip = I° + M (L/2)^2
⭐that is .==》 Ip = I° + ML^2/ 4 ...
⭐APPLIED PARALLEL AXIS THEOREM ...
⭐OPTION (B)
_____________________________
⭐hope it helps u....☺
Here is Your Answer...!!!
_______________________
⭐Actually welcome to the concept of the ROTATIONAL Dynamics...
⭐Basically we know that ... to find the Moment of inertia along any axis parallel to the Central Axis of the rotation is given as ...
⭐Ip = Icm + M ( length or dimension from the centre of the body to the point on which to find inertia )^2 .
⭐So applying here as given ....we get
⭐Moment of inertia of the axis passing through the midpoint perpendicular to the length is = l°
⭐And to find the inertia from the midpoint to the end of rod ...
⭐The effective lenght will L/2 as we are counting from the mid point ...
⭐Thus substituting in above formula we get ...
⭐Ip = I° + M (L/2)^2
⭐that is .==》 Ip = I° + ML^2/ 4 ...
⭐APPLIED PARALLEL AXIS THEOREM ...
⭐OPTION (B)
_____________________________
⭐hope it helps u....☺
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