plz solve with explanation.
in the figure, the median BD bisect Angle B . Prove that AB=BC
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Step-by-step explanation:
IN ΔABD AND ΔBDC
BD IS A MEDIAN
∴ AD = CD
∴ ∠ABD = ∠CBD
NOW IN ΔABD AND ΔBDC
AD = CD(PROVED ABOVE)
∠ABD = ∠CBD(PROVED ABOVE)
BD = BD (COMMON)
ΔABD ≅ ΔBDC
HENCE AB = AC
mili1978pikugm65:
WRONG WRONG
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