Question

plz solve with steps

Answer 1

Btw its not clears !! but I observed that ,
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A particle moves in first C to T and then T to S { see attached my pic }

we know,
displacement is the smallest separation between intial to final position of object .
e.g displacement between CS = √( CT²+ TS²)
but in question ,
CT = L,
TS = L
so, displacement = √(L² + L²) = √2L

distance = CT + TS
distance = L + L = 2L

Answer 2

The path length = AB + AC =   l + l = 2l 

The displacement  is shortest distance between A and C so displacement = AC

As angle between two vectors is 90 so resultant vector is √(A² + B² + 2cosФ) 


= √(l² +l² + cos 90 ) 

= √2l² + 0 

= √2l²

= l√2
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