plz solve with steps
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Btw its not clears !! but I observed that ,
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A particle moves in first C to T and then T to S { see attached my pic }
we know,
displacement is the smallest separation between intial to final position of object .
e.g displacement between CS = √( CT²+ TS²)
but in question ,
CT = L,
TS = L
so, displacement = √(L² + L²) = √2L
distance = CT + TS
distance = L + L = 2L
_________________________________________________________
A particle moves in first C to T and then T to S { see attached my pic }
we know,
displacement is the smallest separation between intial to final position of object .
e.g displacement between CS = √( CT²+ TS²)
but in question ,
CT = L,
TS = L
so, displacement = √(L² + L²) = √2L
distance = CT + TS
distance = L + L = 2L
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Answered by
1
The path length = AB + AC = l + l = 2l
The displacement is shortest distance between A and C so displacement = AC
As angle between two vectors is 90 so resultant vector is √(A² + B² + 2cosФ)
= √(l² +l² + cos 90 )
= √2l² + 0
= √2l²
= l√2
_________________________________________________________
The displacement is shortest distance between A and C so displacement = AC
As angle between two vectors is 90 so resultant vector is √(A² + B² + 2cosФ)
= √(l² +l² + cos 90 )
= √2l² + 0
= √2l²
= l√2
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