plz solve with steps
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let the smallest no be x
thus the no are x , x+2 , x+4 and x+6
the sum of all the no is 36
x+x+2+x+4+x+6 = 36
4x + 12 = 36
4x = 36 - 12
4x = 24
x = 24/4
x = 6
thus the no are 6(x) , 8(x+2) , 10(x+4) and 12(x+6)
THUS THE SMALLEST AND THE LARGEST NO ARE 6 AND 12 RESPECTIVELY
HOPE IT HELPS !!!
PLZ MARK MY ANSWER AS BRAINLIEST !!
thus the no are x , x+2 , x+4 and x+6
the sum of all the no is 36
x+x+2+x+4+x+6 = 36
4x + 12 = 36
4x = 36 - 12
4x = 24
x = 24/4
x = 6
thus the no are 6(x) , 8(x+2) , 10(x+4) and 12(x+6)
THUS THE SMALLEST AND THE LARGEST NO ARE 6 AND 12 RESPECTIVELY
HOPE IT HELPS !!!
PLZ MARK MY ANSWER AS BRAINLIEST !!
ishan1310:
thanx
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take a clear photo. then Post
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