Question

plz solve with steps
out of the four consecutive odd nos the ratio of one more than the largest to three more than than the smallest odd nos is 5:3 find all the four nos
hint : take 4 odd consecutive odd nos x ,x+2, x+4, x+6

Answer 1

Let the numbers be x, x + 2, x + 4 and x + 6

According to question,

( x + 6 + 1) / ( x + 3) = 5 / 3

=> ( x + 7) / (x +3) = 5/ 3

=> 3x + 21 = 5x + 15

=> 5x - 3x = 21 - 15

=> 2x = 6

=> x = 3

First number = 3

Second number = 3 + 2 = 5

Third number = 3 + 4 = 7

Fourth number = 3 + 6 = 9

Answer 2

Answer:

3,5,7,9

Step-by-step explanation:

add all and let it be x