Question

plz solve with steps ...

: the minute hand of a clock is 15 cm long what area does it pass over in 1 hour

Answer 1

Method - 1:

Given, radius of the circle = 15 cm.

We know that Minute hand completes 360° in 1-hour.

So, Ф = 360.

Now,

We know that Area of sector = (Ф/360) * πr^2

⇒ (360/360) * 3.14 * (15)^2

⇒ 3.14 * 15 * 15

⇒ 706.5 cm^2.

Therefore, the area swept by the minute hand = 706.5 cm^2.

Hope this helps!

Answer 2

Here your answer goes ..........

• The minute hand of a clock is 15 cm long  in one hour it means it covers the whole clock in one hour

• In this question we have to find area

• We know that area of circle =  $\pi r^{2}$

• In a clock r is a radius of minute hand

• Take $\pi$ = 3.14

• By putting the values in the formula we get

===> 3.14 × 15 × 15

====> 3.14 × 225

=====> 706.5 $cm^{2}$

Therefore , the minute hand of a clock of about 15 cm long then 706.5 $cm^{2}$ it pass over in 1 hour

$\leq Be Brainly \geq$

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