Question

plz solved four questions plz plZ plz ​

Answer 1

Answer:

i hop it helpful

thnk u

......

Answer 2

$\:\: \underline{\underline{\bf{\large\mathfrak\red{~~Solution~~}}}}$

(1)

A=35°

B=55°

therefore...

C=180°-(A+B)=180°-(35°+55°)=90°

so...AB is hypotenuse here...

therefore according to Pythagorean theorem...

AB²=AC²+BC²

(2)

(a)

$x = \sqrt{6 {}^{2} + 8 {}^{2} } \\ \: \: \: \: = \sqrt{36 + 64} = \sqrt{100} = 10$

(b)

$x = \sqrt{7 {}^{2} + 24 {}^{2} } \\ \: \: \: \: = \sqrt{49 + 576} = \sqrt{625} = 25$

(c)

$x = 2 \times \sqrt{35 {}^{2} - 28 {}^{2} } \\ \: \: \: = 2 \times \sqrt{7 \times 63} = 42$

(d)

$x = \sqrt{24 {}^{2} - 8 {}^{2} } \\ \: \: \: \: = \sqrt{(24 + 8)(24 - 8)} \\ \: \: \: \: = \sqrt{32 \times 16} = 16 \sqrt{2}$

(9)

the direct distance is ...

$= \sqrt{180 {}^{2} + 240 {}^{2} } \\ = \sqrt{90000} \\ = 300 \: m$

(10)

the diagonal is ....

$= \sqrt{21 {}^{2} + 28 {}^{2} } \\ = \sqrt{1225} \\ = 35 \: \: cm$

$:\: \underline{\underline{\bf{\large\mathfrak{~hope ~this ~help~you~~}}}}$