plz solved this question.
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Picture is blurry .
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Given
∆SNT and ∆TMS
TM is perpendicular to RS
and
SN is perpendicular to RT
In ∆SNT and ∆ TMS
angle TMS = angle SMT (each 90°)
side TM = Side SN (given in the Question)
Side ST = side ST (common base)
there fore ∆SNT is congruent to ∆TMS
By Side angle side congruence criteria.. ..
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