Question

plz solveeee......!!!​

Answer 1

Step-by-step explanation:

I hope u will find helpful this solution

Answer 2

Solution :-

∫2ˣ.eˣ

$Combine\ exponentials.$

= ∫$e^{(ln2+1) x}dx$

$Substitute\ u=(ln2+1)x=>\frac{du}{dx} =ln2+1=>dx=(\frac{1}{ln2+1} )du$

=  $\frac{1}{ln2+1}$ ∫$e^u}du$

= $\frac{e^u}{ln2+1}$

$Undo\ substitution\ u=(ln2+1)x$

= $\frac{e^{(ln2+1)x}}{ln2+1}$

= $\frac{2^{x}e^{x}}{ln2+1}$

You can further manipulate answer according to the answer key.

Remarks :-

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