Physics, asked by madhavitimmaraju, 1 year ago

plz some slove fast​

Attachments:

Answers

Answered by raj3294
1

Answer:

Explanation:

6 R OHMS ARE IN PARALLEL

R NET = R/6

THIS R/6 IS IN SERIES WITH TWO OTHER R OHMS IN SERIES

R NET = R/6+R+R

          = R/6+2 R

          = R+12 R/6

          = 13 R/6.

HOPE THIS HELPS.

Answered by DrNykterstein
0

Equivalent resistance in connected in parallel:

1/E.R = 1/R + 1/R + 1/R + 1/R + 1/R + 1/R

1/E.R = 1+1+1+1+1+1/R

1/E.R = 6/R

equivalent Resistance, = R/6

Total resistance of the circuit = R + R + R/6

==> 2R + R/6

==> ( 12R + R ) / 6

==> 13R / 6 Ω

Similar questions