plz some this problem..
Q. Prove that if a number is tripled, then it's cube is 27 times the cube of the given number.
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Hey !!
Here is your answer.. ⬇⬇
Let the no. be x..
➡ Given that if no. is tripled.
x × x × x = x^3
Its triple value = 3x
so,
3x × 3x × 3x = 27x^3
Hence, now take value of x=1
Then, 1 × 1 × 1 = 1
it's triple value = 3( 1 )
3 × 3 × 3 = 27
Hence ,it is proved that if a number is tripled, then it's cube is 27 times the cube of the given number.
Here is your answer.. ⬇⬇
Let the no. be x..
➡ Given that if no. is tripled.
x × x × x = x^3
Its triple value = 3x
so,
3x × 3x × 3x = 27x^3
Hence, now take value of x=1
Then, 1 × 1 × 1 = 1
it's triple value = 3( 1 )
3 × 3 × 3 = 27
Hence ,it is proved that if a number is tripled, then it's cube is 27 times the cube of the given number.
suryamadhab:
thanks for your excellent answer
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