Question

plz someone ans


Present age of mother of Manish is 1 year more than 5 times the present age of Manish. Four years before If the product of their ages was 22 then find the present age of Manish and his mother.​

Answer 1

Step-by-step explanation:

let

present age of Manish = x

present age of Manish's mother = 5x + 1

Manish's age four years ago = x - 4

Manish's mother's age four years ago = 5x + 1 - 4

= 5x - 3

given that (5x - 3) * (x-4) = 22

=> 5x² - 20x - 3x + 12 = 22

=> 5x² - 23x - 10 = 0

=> 5x² - 25x + 2x - 10 = 0

=> 5x(x - 5) + 2(x - 5) = 0

=> (5x + 2)(x - 5) = 0

=> x = -2/5 ×

=> x = 5 √

therefore Manish's present age = 5 years

Manish's Mother's present age =5*5+1 = 26 years

Answer 2

Answer:

26 years

Step-by-step explanation:

Let

present age of manish= x

present age if manish's mother=5x+1

manish's age 4 years ago=x-4

manish's mother age 4 years ago=5x+1-4

=5x-3

given that(5x-3)×(x-4)=22

=

$5x { } ^{2} - 20 x - 3x + 12 = 22$

=

$5 {x}^{2} - 23x - 10 = 0$

=

$5 {x}^{2} - 25x + 2x - 10 = 0$

=

$5x(x - 5) + 2(x - 5) = 0$

=

$(5x + 2)(x - 5) = 0$

=

$x = - 2 \5x$

=

$x = 5 \sqrt{}$

Therefore manish's present age =5 years

manish's mother present age =5×5+1

=26 years