Question

plz someone ans this question...​

Answer 1

$\bf \huge {\underline {\underline \red{QuEsTiOn}}}$

⠀⠀⠀⠀⠀⠀⠀

In given figure, AD = BC, AC = BD. Prove that ∠ADB = ∠ACB.

⠀⠀⠀⠀⠀⠀⠀

$\bf \huge {\underline {\underline \red{AnSwEr}}}$

⠀⠀⠀⠀⠀⠀⠀

Given

⠀⠀⠀⠀⠀⠀⠀

• AD = BC

⠀⠀⠀⠀⠀⠀⠀

• AC = BD

⠀⠀⠀⠀⠀⠀⠀

To Prove

⠀⠀⠀⠀⠀⠀⠀

• ∠ADB = ∠ACB

⠀⠀⠀⠀⠀⠀⠀

Solution

⠀⠀⠀⠀⠀⠀⠀

In △ADB and △ACB

⠀⠀⠀⠀⠀⠀⠀

AD = BC [ given ]

AC = BD [ given ]

AB = AB [ common ]

⠀⠀⠀⠀⠀⠀⠀

Therefore,△ADB ≅ △ACB [ by SSS congruence ]

⠀⠀⠀⠀⠀⠀⠀

∠ADB = ∠ACB [ by CPCT ]