Question

plz someone answer this :-a wooden block floats in water with two third of its volume sumerged find 1 density of wood 2 when the same block is placed in oil and three quater of its volume is immersed in oil calculate the density of oil​

Answer 1

$see the above attachment!✌️$

Answer 2

Correct Question:

A wooden block floats in water with two-third of its volume submerged find

• density of wood
• when the same block is placed in oil and three-quarters of its volume is immersed in oil calculate the density of oil.​

Solution :

$\sf{(1)}$

Given data,

• Volume of the wooden block = V
• Volume of the submerged part = Volume of water displaced = 2V/3
• Density of water (ρ) = 1g cm⁻³

⇒ Weight  = buoyancy

⇒ Volume of the wood x density of wood = Volume of the water displaced        

                                                                                      x  density of water                                                                                          

⇒ V x ρ = 2V/3 x ρ'

⇒ ρ = 2/3 x 1

⇒ ρ = 2/3

The density of wood is 2/3 gm cm⁻³.

_______________________

$\sf{(2)}$

Given data,

• Volume of the wooden block = V
• Volume of the submerged part = Volume of water displaced = 3V/4
• Density of wood (ρ') = 2/3 g cm⁻³

⇒ Weight  = buoyancy

⇒ Volume of the wood x density of wood = Volume of the oil displaced        

                                                                                      x  density of oil                                                                                          

⇒ V x ρ' = 3V/4 x ρ"

⇒ ρ"  = 2 x 4 / 3 x 3

⇒ ρ" = 8/9

The density of wood is 8/9 gm cm⁻³.